ࡱ> .0-q` ?bjbjqPqP 4H::\>$n8888$~hN u 88ccc88cccc8b `%kJc<0c44c4cHc  Y D >> M 628 Cu 3: Ta c s  (C6H10O5)n ! 2C2H5OH Vy m = 23.40%.0,8.162:2:80%:46 = 16,2 kg. Chn D Cu 11: X l Ba(HCO3)2, Y l Na2CO3, Z l KHSO4. Ba(HCO3)2 + Na2CO3 ! BaCO3 + 2NaHCO3 Na2CO3 + 2KHSO4 ! Na2SO4 + K2SO4 + CO2 + H2O Ba(HCO3)2 + 2KHSO4 ! BaSO4 + K2SO4 + 2CO2 + 2H2O. Chn D Cu 25: A Gm cc cht: isoamyl axetat, phenylamoni clorua, poli(vinyl axetat), glyxylvalin (Gly-Val), triolein. Cu 26: Cht Y l HCOONH4 v cht Z l NH2CH2COONH4 vi s mol tng ng l x v y. Ta c x + y = nNaOH = 0,2 v 63x + 92y = 16,08 ! x = 0,08 ; y = 0,12 + Xt X tc dng HCl d th m = 0,12 mol ClNH3CH2COOH = 13,38 gam. Chn C Cu 27: B  EMBED Equation.DSMT4  Dung dch Y gm NaOH: x mol v NaAlO2: y mol nn %Na (X) = 23(x+y).100/ 4,43  EMBED Equation.DSMT4  Khi HCl: 0,06 mol th HCl + NaOH  EMBED Equation.DSMT4  NaCl + H2O HCl + NaAlO2 + H2O EMBED Equation.DSMT4  NaCl + Al(OH)3 nn 0,06 = x +  EMBED Equation.DSMT4  (I)  EMBED Equation.DSMT4 Khi HCl: 0,13 mol th HCl + NaOH  EMBED Equation.DSMT4  NaCl + H2O HCl + NaAlO2 + H2O EMBED Equation.DSMT4  NaCl + Al(OH)3 3HCl + Al(OH)3  EMBED Equation.DSMT4 AlCl3 + 3H2O nn 0,13 = x + y +3 (y - EMBED Equation.DSMT4  ) (II)  EMBED Equation.DSMT4 T (I) v (II) th x + y = 0,07 nn %Na = 36,34% Cu 31: D Pht biu ng l: (2)(4)(6)(7) Cu 32: Chn C gm HCOONH4, NaHSO3, Al2O3, Al, (NH2)2CO. Cu 33: D X l C3H5(OOCC17H33)(OOC-C15H31)(OOC-C17H35) suy ra cng thc phn t l C55H104O6. Ta c C55H104O6 + 78O2 ! 55CO2 + 52H2O 0,012 suy ra V = 0,012.78.22,4 = 20,9664 lt. Cu 37: B V nCH4 = 2 nC3H8O3 nn coi hh gm: CH4O (2a mol), C3H8O (a mol), C2H6O v CnH2nO2. Qui hh X v dang: CmH2m+2O v CnH2nO2 mol x y X + O2 ! CO2 + H2O mol 0,305 0,31 z Bo ton O: x + 2y + 0,305.2 = 0,31.2 + z (I) Li c: n CmH2m+2O = nH2O  nCO2 ! x = z  0,31 (II). T (I)(II) ! y = 0,16 mol. s mol CO2 sinh ra khi t CnH2nO2 l: yn < 0,31! n < 1,93 ! n= 1 axit l HCOOH Cht rn gm: HCOONa: 0,16 mol, NaOH d = 0,045mol ! a = 12,68 g. Cu 38: B Cho AgNO3 vo dung dich sau in phn c kh NO thot ra ! trong Y cn HCl d. dd Y gm: FeCl3, FeCl2, CuCl2 v HCl d. in phn dd Y n khi  catot c kh thot ra th dng in phn ! H+ cha b kh. Cc (-) <>@DFHJLVXZ\   $ & * 6 8 : < H J N P ^ ` r t v z | ͵تh`h)TH*mH sH h`h)TmH sH h`h)TH*mH sH h`h)TmH sH h`h)T5mH sH h`h)TH*mHsHh`h)TmHsHh`h)TmHsHh`h)T5mHsHh`h}f5CJaJmHsH5b* v D X ( Z  _$ w +<]a$gd}f$ w +<7$8$H$]a$gdgd}f $<a$gd)T gd)T  gd)T$a$gd-?       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Fe2+ 2Cl- + 2e ! Cl2 0,08 0,08 0,08 (0,08+2a) (0,04+a) Cu2+ + 2e ! Cu a 2a a mdd gim = 64a + 71(0,04 +a) ! a = 0,08 mol. Cu + 2Fe3+ ! 2Fe2++ Cu2+ 0,08 0,16 0,16 0,08 Hn hp X gm FeO.Fe2O3 ( x mol), Fe2O3 ( y mol) 232x + 160y = 27,92  0,08.64 = 22,8 (1) 2x + 2y = 0,24 (2) T(1)(2) ! x = 0,03 mol, y = 0,09 mol. dd sau in phn c: x + 0,16 + 0,08 = 0,29 mol Fe2+ 0,9  0,82 = 0,08 mol H+d v 0,9  0,08- 0,08.2 = 0,66 mol Cl-d Thm AgNO3 vo, xy ra cc phn ng 3Fe2+ + 4H+ + NO3- ! 3Fe3+ +NO +H2O. Fe2+ + Ag+ ! Fe3+ + Ag. Ag+ + Cl- ! AgCl m! = mAg + mAgCl = 0,23. 108 + 0,66. 143,5 = 119,55 gam. Cu 39: Bo ton khi lng tnh nCO2 = 0,3 mol = nH2O nn s mol C2H5OH v CH3COOC2H3 l bng nhau (x mol); cc cht cn li c dng (CH2O)n. Vy X gm C2H5OH ; CH3COOC2H3; CH2O vi s mol l x, x v y Ta c 46x + 86x + 30 y = 8,28 v nH2O = 0,3 = 3x + 3x + y ! x = 0,015 v y = 0,21 Vy %m CH3COOC2H3 = 0,015.86:8,28.100% = 15,58%.Chn D Cu 40: Xem peptit X l CnH2n-1ON v H2O vi s mol tng ng l 16x v x. t chy X ta c CnH2n-1ON + (3n-1,5)/2 O2 ! nCO2 + (n-0,5)H2O Ta c 16x.(3n-1,5).1/2 = nO2 = 1,02 (*). + Y l CnH2nO2NNa + 1/2(3n-1,5)O2! 1/2Na2CO3 + (n-0,5)CO2 + nH2O +1/2N2 16x 8x(3n-1,5) 16x(n-0,5) 8x Ta c 6,07 = O2d + N2(to ra) + CO2 + N2 (khng kh) 6,07 = 1,25 - 8x(3n-1,5) + 8x + 16x(n-0,5) + 5 (**) T (*) v (**) gii x =0,02; n = 2,625 . Vy m = (14n+29).16x + 18x = 21,4. 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